题目描述
汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count CREATE TABLE `departments` ( `dept_no` char(4) NOT NULL, `dept_name` varchar(40) NOT NULL, PRIMARY KEY (`dept_no`)); CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL, `dept_no` char(4) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`dept_no`)); CREATE TABLE IF NOT EXISTS `titles` ( `emp_no` int(11) NOT NULL, `title` varchar(50) NOT NULL, `from_date` date NOT NULL, `to_date` date DEFAULT NULL);
输入描述:
无
输出描述:
dept_no | dept_name | title | count |
---|---|---|---|
d001 | Marketing | Senior Engineer | 1 |
d001 | Marketing | Staff | 1 |
d002 | Finance | Senior Engineer | 1 |
d003 | Human Resources | Senior Staff | 1 |
d004 | Production | Senior Engineer | 2 |
d005 | Development | Senior Staff | 1 |
d006 | Quality Management | Engineer | 2 |
d006 | Quality Management | Senior Engineer | 1 |
select A.dept_no,departments.dept_name,A.title,A.countfrom departments INNER JOIN(select dept_emp.emp_no, dept_emp.dept_no,t.title,count(t.title) as countfrom dept_emp INNER JOIN titles ton dept_emp.emp_no=t.emp_no and dept_emp.to_date='9999-01-01' and t.to_date='9999-01-01'GROUP BY dept_emp.dept_no,t.title)as AWHERE departments.dept_no=A.dept_no
最重要的是对其进行二次分组 统计相同部门,相同title 的数目。